Web2009 TMTA PRECALCULUS TEST 34. Which of the following expressions is equivalent to sin(x + y)?(a) sin x + sin y (b) sin x sin y (c) sin x cos x (d) cos x cos y + sin x sin y (e) sin x cos y + cos x sin y 35. Simplify ((x-1 - y-1)-1 + z-1)-1 (a) (yz – xz)/(xyz - x + y) (b) (xz + yz)/(xyz - x + y) (c) (xz + yz)/(xyz + x – y)(d) (yz - xz)/(xyz+ x – y) (e) ( + x) WebQuestion: Differentiate the following function. y = 2 csc(x) + 7 cos(x) Step 1 csc (r) cot (2) (It's important to simply Recall that the derivative of csc(x) is-cse(x)cot(x) memorize the derivatives of all six trigonometric functions.) Step 2 Since the derivative of csc(x) is -csc(x) cot(x), then the derivative of 2 cscx) is Submit Skin_(you cannot come back?
Solved Question 6 Find the derivative. y = (csc x + cot - Chegg
WebFind the derivative. y = 8/sin(x) + 1/cot(x) A) y' = 8 csc(x) cot(x) - sec^2(x) B) y' = -8 csc(x) cot(x) + sec^2(x) C) y' = -csc(x) cot(x) - 8sec^2(x) D) y' = 8csc(x) cot(x) - csc^2(x) E) y' = 8 cos(x) - csc^2(x) Previous question Next question. Get more help from Chegg . Solve it with our Calculus problem solver and calculator. WebThis is an implicit function.. 3 cot(x + y) = cos y 2For the left hand side, we put u = x + y.. Differentiating 3 cot u gives us: `3(-csc^2 u)((du)/(dx))` Substituting for `u` and performing the `(du)/(dx)` part gives us: `-3 csc^2(x+y)(1+(dy)/(dx))` On the right hand side, we let u = y 2.Differentiating `cos u` gives us: `(-sin u)((du)/(dx))` theoretikum halle
Derivatives of sec(x) and csc(x) (video) Khan Academy
WebMar 5, 2015 · Mar 5, 2015. You can write: ∫csc(x)cot(x)dx = as: ∫ 1 sin(x) cos(x) sin(x) dx = ∫ cos(x) sin2(x) dx =. But: d[sin(x)] = cos(x)dx so your integral becomes: ∫ cos(x) sin2(x) dx = ∫sin−2(x)d[sin(x)] = − 1 sin(x) + c. Where you integrate sin−2(x) as if it was x2 in a normal integral where you have dx. WebDifficult Problems. 1. Solved example of simplify trigonometric expressions. Applying the trigonometric identity: cot2(θ) csc(θ)2 1. 3. Apply the trigonometric identity: 1-\sin\left (x\right)^2 1−sin(x)2 =\cos\left (x\right)^2 cos(x)2. \frac {\cos\left (x\right)^2} {\cot\left (x\right)^2} os. 4. WebSep 14, 2014 · The answer is y' = − 1 1 +x2. We start by using implicit differentiation: y = cot−1x. coty = x. −csc2y dy dx = 1. dy dx = − 1 csc2y. dy dx = − 1 1 +cot2y using trig identity: 1 +cot2θ = csc2θ. dy dx = − 1 1 + x2 using line 2: coty = x. The trick for this derivative is to use an identity that allows you to substitute x back in for ... theoretisch basisboek hu